250/9=x^2+9

Solution for 250/9=x^2+9 equation:

250/9=x^2+9

We move all terms to the left:

250/9-(x^2+9)=0

We get rid of parentheses

-x^2-9+250/9=0

We multiply all the terms by the denominator


-x^2*9+250-9*9=0

We add all the numbers together, and all the variables

-x^2*9+169=0

Wy multiply elements

-9x^2+169=0

a = -9; b = 0; c = +169;
Δ = b2-4ac
Δ = 02-4·(-9)·169
Δ = 6084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6084}=78$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-78}{2*-9}=\frac{-78}{-18}
=4+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+78}{2*-9}=\frac{78}{-18}
=-4+1/3
$